Parse Comma-Separated Integers into an Array

Code

#include <stdio.h>
#include <stdint.h>
#include <string.h>

void parse_csv_to_array(const char *str, uint8_t *arr, uint8_t *count) {
    // Your logic here
    *count = 0;

    char numeric_string[4] = {0};
    uint8_t numeric_value = 0;
    int numeric_string_index = 0;

    int str_len = strlen(str);

    for(int i=0; i <= str_len; i++){
        if(str[i] == ',' || str[i] == '\0'){

            //terminate the numeric_string
            numeric_string[numeric_string_index] = '\0';

            //convert numeric_string to numeric_value
            numeric_value = 0;
            for (int j = 0; j < numeric_string_index; j++) {
                numeric_value = numeric_value * 10 + (numeric_string[j] - '0');
            }

            //append the numeric value to the final result arr
            arr[(*count)++] = numeric_value;

            //resset numeric_string and index
            memset(numeric_string, 0, sizeof(numeric_string));
            numeric_string_index = 0;


        }
        else{
            if(numeric_string_index < sizeof(numeric_string) - 1){  //adding upper limit constraint
                numeric_string[numeric_string_index++] = str[i];
            }
            
        }
    }
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    uint8_t arr[20];
    uint8_t count = 0;

    parse_csv_to_array(str, arr, &count);

    for (uint8_t i = 0; i < count; i++) {
        printf("%u", arr[i]);
        if(i < count - 1){
            printf(" ");
        }
    }
    return 0;
}

Solving Approach