Parse Comma-Separated Integers into an Array

Code

#include <stdio.h>
#include <stdint.h>

void parse_csv_to_array(const char *str, uint8_t *arr, uint8_t *count) {
    // Your logic here
    uint8_t current=0;
    *count=0;

for(int i=0;str[i]!='\0';i++){
    if(str[i]>='0' && str[i]<='9'){
        current= current*10 + (str[i]-'0');
    }else if(str[i]==','){
        arr[*count]=current;
        (*count)++;
        current=0;
    }
}
arr[*count]=current;
(*count)++;
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    uint8_t arr[20];
    uint8_t count = 0;

    parse_csv_to_array(str, arr, &count);

    for (uint8_t i = 0; i < count; i++) {
        printf("%u", arr[i]);
        if(i < count - 1){
            printf(" ");
        }
    }
    return 0;
}

Solving Approach