97. Parse Comma-Separated Integers into an Array

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Code

#include <stdio.h>
#include <stdint.h>

void parse_csv_to_array(const char *str, uint8_t *arr, uint8_t *count) {
    // Your logic here
    uint8_t cv = 0;
    uint8_t flag = 0;
    uint8_t i = 0;
    while(*str != '\0')
    {
        if( *str >= '0' && *str <= '9')
        {
            cv = (cv*10) + (*str -'0');
            flag = 1;
        }
        else if(*str == ',')
        {
            if(flag)
            {
                arr[i] = cv;
                printf("%d ", arr[i]);
                i++;
                flag = 0;
                cv = 0;
            }
        }
        str++;
}

if(flag)
{
    arr[i] = cv;
    printf("%d", arr[i]);
    i++;
}
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    uint8_t arr[20];
    uint8_t count = 0;

    parse_csv_to_array(str, arr, &count);

    for (uint8_t i = 0; i < count; i++) {
        printf("%u", arr[i]);
        if(i < count - 1){
            printf(" ");
        }
    }
    return 0;
}

Solving Approach

 

 

 

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