Parse Comma-Separated Integers into an Array

Code

#include <stdio.h>
#include <stdint.h>


uint8_t str_to_u8(char *str, uint8_t digits) {
    uint8_t result = 0;
    for (int i = 0; i < digits; i++) {
        result = result * 10 + str[i] - '0';
    }
    return result;
}

void parse_csv_to_array(const char *str, uint8_t *arr, uint8_t *count) {
    // Your logic here
    char *start = (char *)str;
    char *read = (char *)str;
    *count = 0;
    
    for (;;) {
        if (*read == ',') {
            arr[*count] = str_to_u8(start, read-start);
            *count += 1;
            ++read;
            start = read;        
        }
        else if (*read == '\0') {
            arr[*count] = str_to_u8(start, read-start);
            *count += 1;
            break;
        }
        else {
            ++read;
        }
    }
}


int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    uint8_t arr[20];
    uint8_t count = 0;

    parse_csv_to_array(str, arr, &count);

    for (uint8_t i = 0; i < count; i++) {
        printf("%u", arr[i]);
        if(i < count - 1){
            printf(" ");
        }
    }
    return 0;
}

Solving Approach