Parse Comma-Separated Integers into an Array

Code

#include <stdio.h>
#include <stdint.h>
#include <ctype.h>
#include <string.h>
#include <stdlib.h>

void parse_csv_to_array(const char *str, uint8_t *arr, uint8_t *count) 
{
    uint8_t arr_index = 0;
    char num_string[4];
    uint num_string_index = 0; 
    uint8_t number;
    

    for(int i = 0; i <= strlen(str); i++)
    {

        if(isdigit(str[i]))
        {
          num_string[num_string_index] = str[i];
          num_string_index++;
        }
        else
        {
          num_string[num_string_index] = '\0';
          number = atoi(num_string);
          arr[arr_index] = number;
          *count += 1;
          arr_index++;
          memset(num_string, 0, sizeof(num_string));
          num_string_index = 0;
        }
    }
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    uint8_t arr[20];
    uint8_t count = 0;

    parse_csv_to_array(str, arr, &count);

    for (uint8_t i = 0; i < count; i++) {
        printf("%u", arr[i]);
        if(i < count - 1){
            printf(" ");
        }
    }
    return 0;
}

Solving Approach