Parse Comma-Separated Integers into an Array

Code

#include <stdio.h>
#include <stdint.h>
#include <math.h>

void parse_csv_to_array(const char *str, uint8_t *arr, uint8_t *count) {
    // Your logic here
    int cnt = 0;
    int pos = 0;
    *count=0;
    while(str[cnt] != 0){
        if(str[cnt]==','){
            arr[*count] = 0;
            while(pos>0){
                arr[*count]+=(str[cnt-pos]-48)*pow(10,pos-1);
                pos--;
            }
            (*count)++;
        }
        else{
            pos++;
        }
        cnt++;
    }
    
    arr[*count] = 0;
            while(pos>0){
                arr[*count]+=(str[cnt-pos]-48)*pow(10,pos-1);
                pos--;
            }
            (*count)++;
            
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    uint8_t arr[20];
    uint8_t count = 0;

    parse_csv_to_array(str, arr, &count);

    for (uint8_t i = 0; i < count; i++) {
        printf("%u", arr[i]);
        if(i < count - 1){
            printf(" ");
        }
    }
    return 0;
}

Solving Approach