97. Parse Comma-Separated Integers into an Array

#include <stdio.h>
#include <stdint.h>

int str_to_int(char *str){
    int val=0;
    while(*str){
        val = (val *10)+ (*str-'0');
        str++;
    }
    return val;
}
void parse_csv_to_array(const char *str, uint8_t *arr, uint8_t *count) {
    // Your logic here
    int i=0;
    char numerical[8]={0}; 
    char *num_ptr=numerical;
    while(*str){
        if(*str >= '0' && *str<='9'){
           *(num_ptr++) = *str;
        }
        else if(*str==','){
            *num_ptr='\0';
            *(arr++)=str_to_int(numerical);
            for(int i=0;i<8;i++)numerical[i]=0; 
            num_ptr = numerical;
            *count += 1;  
        }

        str++;
       
    }
    *count +=1;
    *(arr++)=str_to_int(numerical);
   
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    uint8_t arr[20];
    uint8_t count = 0;

    parse_csv_to_array(str, arr, &count);

    for (uint8_t i = 0; i < count; i++) {
        printf("%u", arr[i]);
        if(i < count - 1){
            printf(" ");
        }
    }
    return 0;
}