Print Binary Representation of an 8-bit or 16-bit Value

Code

#include <stdio.h>
#include <stdint.h>

void print_binary(uint16_t val) {
    // Your logic here
    uint16_t k, mask=0x8000;
    uint8_t i;
    uint8_t printsize;
    
    if ((val & 0xFF00) == 0) {
        printsize=8;
        mask = 0x80;
    }
    else  {
        printsize = 16;
        mask = 0x8000;
    }
    for (i=0; i < printsize; i++) {
        k= mask & val;
        if (k == 0) {
            printf("%c", '0');
        }
        else {
            printf("%c", '1');
        }
        mask = mask >> 1;
    }
}

int main() {
    uint16_t val;
    scanf("%hu", &val);
    print_binary(val);
    return 0;
}

Solving Approach

check th eupper byte to see if we print 8 or 16 bits.

using a rolling mask to identify the bits and print them as characters.