Print Binary Representation of an 8-bit or 16-bit Value

Code

#include <stdio.h>
#include <stdint.h>

void print_binary(uint16_t val) {
    // Your logic here
    int x = (val <= 0xFF)? 8: 16;
    int t;
    for (int i = x - 1; i >=0; i--){
        t = (val & (1 << i))? 1 : 0;
        printf("%d",t);
    }
}

int main() {
    uint16_t val;
    scanf("%hu", &val);
    print_binary(val);
    return 0;
}

Solving Approach