Print Binary Representation of an 8-bit or 16-bit Value

Code

#include <stdio.h>
#include <stdint.h>

void print_binary(uint16_t val) {
    // Your logic here
    int bits = 0;
    if(val<=255)
    {
        bits = 8;
    }
    else
    {
        bits = 16;
    }
    for(int i=bits-1; i>=0; i--)
    {
        char bit_char = ((val>>i)&1) ? '1' : '0';
        printf("%c", bit_char);
    }
    
}

int main() {
    uint16_t val;
    scanf("%hu", &val);
    print_binary(val);
    return 0;
}

Solving Approach