Print Binary Representation of an 8-bit or 16-bit Value

Code

#include <stdio.h>
#include <stdint.h>

void print_binary(uint16_t val) {
    // Your logic here
    int size = 0;
    if (val <= 255){
        size = 8;
    } else {
        size = 16;
    }
    int arr[size];
    for (int i=0; i<size; i++){
        int bit = (val >> i) & 1;
        arr[i] = bit;
    }
    for (int i=size-1; i>=0; i--){
        printf("%d", arr[i]);
    }
    printf("\n");
}

int main() {
    uint16_t val;
    scanf("%hu", &val);
    print_binary(val);
    return 0;
}

Solving Approach