Print Binary Representation of an 8-bit or 16-bit Value

Code

#include <stdio.h>
#include <stdint.h>

void print_binary(uint16_t val) {
    // Your logic here
    uint16_t arr[16] = {0};
    int i = 15;
    int flag = 0;
    if(val > 255) flag = 1;
    while (val)   
    {
        arr[i--] = val % 2;
        val = val / 2;
    }
    if(flag){
        for (int i = 0; i < 16; i++)
        {
            printf("%u", arr[i]);
        }
        
    }
    else{
        for (int i = 8; i < 16; i++){
            printf("%u", arr[i]);
        }
    }
}

int main() {
    uint16_t val;
    scanf("%hu", &val);
    print_binary(val);
    return 0;
}

// 10/2 - 0
// 5/2  - 1
// 2/2  - 0
// 1/2  - 1
// 0

Solving Approach