Print Binary Representation of an 8-bit or 16-bit Value

Code

#include <stdio.h>
#include <stdint.h>

void print_binary(uint16_t val) {
    // Your logic here
    int digits,mask;
    if(val <= 255)
    {
        digits = 8;
        mask = 0x80;
    }
    else
    {
        digits = 16;
        mask = 0x8000;
    }
    for(int i = 0;i < digits;i++)
    {   if(mask & (val << i))
        {
            printf("1");
        }
        else
        {
            printf("0");
        }
    }
}

int main() {
    uint16_t val;
    scanf("%hu", &val);
    print_binary(val);
    return 0;
}

Solving Approach