Print Binary Representation of an 8-bit or 16-bit Value

Code

#include <stdio.h>
#include <stdint.h>

void print_binary(uint16_t val) {
    // Your logic here
    int a=(val<=255)?8:16;
    for(int i=a-1;i>=0;i--){
    if(val&(1<<i)){
    printf("1");}
    else  {
        printf("0");}
    }
   
    
    }



int main() {
    uint16_t val;
    scanf("%hu", &val);
    print_binary(val);
    return 0;
}

Solving Approach