Print Binary Representation of an 8-bit or 16-bit Value

Code

#include <stdio.h>
#include <stdint.h>

void print_binary(uint16_t val) {
    // Your logic here
    int len;
    if(val<=255)
    len =8;
    else
    len =16;

    for(int i=0; i<len; i++)
    {
        val & (1<<((len-1)-i)) ? printf("1") : printf("0");
    }
    
}

int main() {
    uint16_t val;
    scanf("%hu", &val);
    print_binary(val);
    return 0;
}

Solving Approach