Print Binary Representation of an 8-bit or 16-bit Value

Code

#include <stdio.h>
#include <stdint.h>

void print_binary(uint16_t val) {
    // Your logic here
    int bits = (val>255)?16:8;
    uint16_t bit_mask = (1U<<(bits-1));
    for(int i = 0; i < bits; i++)
    {
        printf("%u",((val)&(bit_mask>>i))?1:0);
    }
}

int main() {
    uint16_t val;
    scanf("%hu", &val);
    print_binary(val);
    return 0;
}

Solving Approach