Print Binary Representation of an 8-bit or 16-bit Value

Code

#include <stdio.h>
#include <stdint.h>

void print_binary(uint16_t val) {
    // Your logic here
    int i;
    if(val <= 255){
        i=8;
        while(i){
        if((val & (0x80))== (0x80) ){
            printf("1");
        }
        else{
            printf("0");
            }
        val = val << 1;
        i--;
       }
    }
    else{
        i=16;
        while(i){
        if((val & (0x8000))== (0x8000) ){
            printf("1");
        }
        else{
            printf("0");
            }
        val = val << 1;
        i--;
       }

    }
    
}

int main() {
    uint16_t val;
    scanf("%hu", &val);
    print_binary(val);
    return 0;
}

Solving Approach