Print Binary Representation of an 8-bit or 16-bit Value

Code

#include <stdio.h>
#include <stdint.h>

void print_binary(uint16_t val) {
    // Your logic here
    int n= val <= 255 ? 8:16;
    char binary_value[17];
    
    for(int i=0; i<n; i++){
        binary_value[i] = '0'+(val & 0x1);
        val>>=1;
    }

    for(int i=n-1; i>=0; i--){
        printf("%c", binary_value[i]);
    }

}

int main() {
    uint16_t val;
    scanf("%hu", &val);
    print_binary(val);
    return 0;
}

Solving Approach