Print Binary Representation of an 8-bit or 16-bit Value

#include <stdio.h>
#include <stdint.h>

void print_binary(uint16_t val) {
    // Your logic here
    int n = (val <= 0xFF) ? 8 : 16;
    for (int i = n - 1; i >= 0; i--){
        if (val & (1 << i)){
            printf("1");
        } else {
            printf("0");
        }
    }
}

int main() {
    uint16_t val;
    scanf("%hu", &val);
    print_binary(val);
    return 0;
}