Print Binary Representation of an 8-bit or 16-bit Value

Code

#include <stdio.h>
#include <stdint.h>

void print_binary(uint16_t val) {
    // Your logic here
    uint16_t mode_bit = (val & 0xFF00)? 16 : 8 ;
  
    for(int n = 0 ; n < mode_bit ; n++)
    {
        char b = ((val>>(mode_bit-n-1)) & 0x01)? '1' : '0';
        printf("%c",b);
    }
}

int main() {
    uint16_t val;
    scanf("%hu", &val);
    print_binary(val);
    return 0;
}

Solving Approach