Print Binary Representation of an 8-bit or 16-bit Value

Code

#include <stdio.h>
#include <stdint.h>

void print_binary(uint16_t val) {
    // Your logic here
    int size;
    if (val > 255){
        size = 15;
    }
    else{
        size = 7;
    }
    for (int i = size; i >= 0; i--){
        printf("%u", ((val >> i) & 1U));
    }
}

int main() {
    uint16_t val;
    scanf("%hu", &val);
    print_binary(val);
    return 0;
}

Solving Approach