Print Binary Representation of an 8-bit or 16-bit Value

Code

#include <stdio.h>
#include <stdint.h>

void print_binary(uint16_t val) {
    // Your logic here
    int range = (val <= 0xFF) ? 8 : 16;
    for(int i = range-1; i>=0; i--){
        printf("%d", (val >> i) & 1);
    }
}

int main() {
    uint16_t val;
    scanf("%hu", &val);
    print_binary(val);
    return 0;
}

Solving Approach