Print Binary Representation of an 8-bit or 16-bit Value

Code

#include <stdio.h>
#include <stdint.h>

void print_binary(uint16_t val) {
    // Your logic here
    char bits[17];
    uint16_t val_copy = val;
    for(int i=15; i>=0; i--)
    {
        bits[i] = (val_copy & 1U) ? '1' : '0';
        val_copy>>=1;
    }
   
    if(val > 255)
    {
        printf("%s\n", bits);
    }
    else
    {
        printf("%s\n", &bits[8]);
    } 
        
}

int main() {
    uint16_t val;
    scanf("%hu", &val);
    print_binary(val);
    return 0;
}

Solving Approach