Print Binary Representation of an 8-bit or 16-bit Value

Code

#include <stdio.h>
#include <stdint.h>

void print_binary(uint16_t val) {
    /* Using printf */
#if 0    
    if (val <= 255) {
        printf("%08b\n", val);
    } else {
        printf("%016b\n", val);
    }
#elif 1
    for (int i = (((val <= 255) ? 8 : 16) - 1); i>=0; i--) {
        putchar((val & (1 << i)) ? '1' : '0');
    }    
#endif
}

int main() {
    uint16_t val;
    scanf("%hu", &val);
    print_binary(val);
    return 0;
}

Solving Approach