Print Binary Representation of an 8-bit or 16-bit Value

Code

#include <stdio.h>
#include <stdint.h>

void print_binary(uint16_t val) {
    // Your logic here
    uint8_t n;
    if ((val & 0xff00) > 0) {
        n = 16;
    } else {
        n = 8;
    }

    for (int i = n; i != 0; i--) {
        printf("%d", (val >> (i - 1)) & 0x1);
    }
}

int main() {
    uint16_t val;
    scanf("%hu", &val);
    print_binary(val);
    return 0;
}

Solving Approach

Solution is simliar to my logic