Print Binary Representation of an 8-bit or 16-bit Value

Code

#include <stdio.h>
#include <stdint.h>

void print_binary(uint16_t val) {
    // Your logic here
    uint16_t bits = (val <= 0xFF) ? 8 : 16;

    for (int i = 0; i < bits; i++){
        printf("%u", (val >> (bits - i - 1)) & 1);
    }
}

int main() {
    uint16_t val;
    scanf("%hu", &val);
    print_binary(val);
    return 0;
}

Solving Approach