Print Binary Representation of an 8-bit or 16-bit Value

Code

#include <stdio.h>
#include <stdint.h>

void print_binary(uint16_t val) {
    // Your logic here
    uint8_t i = 0;
    if(val <= 255)
    {   
        uint8_t binary8[8]={0};
        for(uint8_t i = 0; i < 8 ; i++)
        {
            binary8[i] = val % 2 ;
            val = val / 2;
        }
        for(int i = 7; i >= 0; i--)
        {
            printf("%d",binary8[i]);
        }
    }
    else 
    {
        uint8_t binary16[16]={0};
        for(uint8_t i = 0; i <16 ; i++)
        {
            binary16[i] = val % 2 ;
            val = val / 2;
        }
        for(int i = 15; i >= 0; i--)
        {
            printf("%d",binary16[i]);
        }
    }
    
}

int main() {
    uint16_t val;
    scanf("%hu", &val);
    print_binary(val);
    return 0;
}

Solving Approach