Print Binary Representation of an 8-bit or 16-bit Value

Code

#include <stdio.h>
#include <stdint.h>

void print_binary(uint16_t val) 
{
    // Your logic here
   int size=sizeof(val)*8;
    if(((val>>8)&0xFF)==0)
    {
        size=8;
    }
   for(int i=size-1;i>=0;i--)
   {
       if(val&(1U<<i))
          printf("1");
          else
          printf("0");
          

   }
}

int main() {
    uint16_t val;
    scanf("%hu", &val);
    print_binary(val);
    return 0;
}

Solving Approach