Print Binary Representation of an 8-bit or 16-bit Value

Code

#include <stdio.h>
#include <stdint.h>

void print_binary(uint16_t val) {
    // Your logic here

    int bit = (val <= 255) ? 8 : 16;


    uint16_t mask = 1U << bit-1;

    for( int i = 0; i< bit; i++){
        printf("%d", (val & mask) != 0);
        mask = mask >> 1;
    }
}

int main() {
    uint16_t val;
    scanf("%hu", &val);
    print_binary(val);
    return 0;
}

Solving Approach

 

 

 

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Input

10

Expected Output

00001010