Print Binary Representation of an 8-bit or 16-bit Value

Code

#include <stdio.h>
#include <stdint.h>

void print_binary(uint16_t val) {
    // Your logic here
    if(0<= val && val <= 255){
     for(int i = 7; i >= 0; i--){
        uint8_t mask = ( 1 << i);
        if((val & mask ) > 0){
            printf("1");
        }
        else{
            printf("0");
        }
     }
    }


        else{
     for(int i = 15; i >= 0; i--){
        uint16_t mask = ( 1 << i);
        if((val & mask ) > 0){
            printf("1");
        }
        else{
            printf("0");
        }
     }
    }
}

int main() {
    uint16_t val;
    scanf("%hu", &val);
    print_binary(val);
    return 0;
}

Solving Approach