Print Binary Representation of an 8-bit or 16-bit Value

Code

#include <stdio.h>
#include <stdint.h>

void print_binary(uint16_t val) {
    // Your logic here
   
    int binary[16]={false};
    
    
    int i=0;
    while(val>0){
        binary[i]= val%2;
        val=val/2;
        i++;
    }
    if(i>8){
for(int j=15;j>=0;j--){
    printf("%d",binary[j]);
}}
else if(i<=8){for(int j=7;j>=0;j--){
    printf("%d",binary[j]);
}}}
    

int main() {
    uint16_t val;
    scanf("%hu", &val);
    print_binary(val);
    return 0;
}

Solving Approach