Print Sum of Even Numbers

Code

#include <stdio.h>

int sum_even_numbers(int *ptr, int n) {
    // Your logic here
    int i, result=0, *p;
    
    for (p=ptr, i=0; i<n; i++) {
        if ((*p & 0x1) == 0) {
            result += *p;
        }
        p++;
    }
    return result;
}

int main() {
    int n;
    scanf("%d", &n);

    int arr[100];
    for (int i = 0; i < n; i++) {
        scanf("%d", &arr[i]);
    }

    int result = sum_even_numbers(arr, n);

    printf("Sum = %d", result);

    return 0;
}

Solving Approach

use a pointer to start at top of list and advance testing for even numbers