Print Sum of Even Numbers

Code

#include <stdio.h>

int sum_even_numbers(int *ptr, int n) {
    int sum = 0;
    if (n%2 != 0 && *(ptr+n/2)%2==0){
        sum = *(ptr+n/2);
    }
    else sum = 0;
    for (int i = 0; i < n/2; i++){
        sum += !(*(ptr+i)%2)*(*(ptr+i));
        sum += !(*(ptr+n-i-1)%2)*(*(ptr+n-i-1));
    }
    return sum;
}

int main() {
    int n;
    scanf("%d", &n);
    int arr[100];
    for (int i = 0; i < n; i++) {
        scanf("%d", &arr[i]);
        
    }
    int result = sum_even_numbers(arr, n);
    printf("Sum = %d", result);

    return 0;
}

Solving Approach