Replace Bit Field in a 32-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint32_t replace_field(uint32_t reg, uint32_t val, uint8_t pos, uint8_t len) {
    // Your code here
    // I think this question has two solutions
    //First solution
    // uint32_t reg1, mask = ((1<<len)-1)<<pos;
    // reg = (reg &= ~mask) | (val<<pos);
    // return reg;
    // Second solution
    uint32_t reg_arr[32], val_arr[32];
    for(uint8_t i=0; i<32; i++){
        val_arr[i] = (val>>i)&1;
    }
    for(uint8_t i=0; i<32; i++){
        reg_arr[i] = (reg>>i)&1;
    }
    for(uint8_t i=0; i<len; i++){
        if(val_arr[i]==1 && reg_arr[pos+i]==1){
            reg |= (1<<((pos+i)));
        }else
        if(val_arr[i]==1 && reg_arr[pos+i]==0){
            reg |= (1<<(pos+i));
        }else
        if(val_arr[i]==0 && reg_arr[pos+i]==1){
            reg &= ~(1<<(pos+i));
        }else
        if(val_arr[i]==0 && reg_arr[pos+i]==0){
            reg &= ~(1<<(pos+i));
        }
    }
    return reg;
}

int main() {
    uint32_t reg, val;
    uint8_t pos, len;
    scanf("%u %u %hhu %hhu", &reg, &val, &pos, &len);
    printf("%u", replace_field(reg, val, pos, len));
    return 0;
}

Solving Approach

 

 

 

Upvote
Downvote
Loading...

Input

255 0 4 4

Expected Output

15