Reverse an Array Using Only Pointers

Code

#include <stdio.h>

void reverse_array(int *ptr, int n) {
    // Your logic here
    for (int i = 0; i < n / 2; i++) {
        // get ptr to address of last element in array
        int* last_ptr = ptr + (n - 1 - i);
        int* first_ptr = ptr + i;

        // Store first element in temp
        int temp = *first_ptr;

        // Change first element to last element
        *first_ptr = *last_ptr;

        // Change last element to temp
        *last_ptr = temp;
    }
}

int main() {
    int n;
    scanf("%d", &n);

    int arr[100];
    for (int i = 0; i < n; i++) {
        scanf("%d", &arr[i]);
    }

    reverse_array(arr, n);

    for (int i = 0; i < n; i++) {
        printf("%d", arr[i]);
        if(i < n-1){
            printf(" ");
        }
    }

    return 0;
}

Solving Approach

 

 

 

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Input

5 1 2 3 4 5

Expected Output

5 4 3 2 1