50. Reverse an Array Using Only Pointers

Back To All Submissions
Previous Submission
Next Submission

Code

#include <stdio.h>

void reverse_array(int *ptr, int n) 
{
    // Your logic here
    for (int i = 0; i < n/2; ++i)
    {
        *(ptr + i) ^= *(ptr + n - 1 - i);
        *(ptr + n - 1 - i) ^= *(ptr + i);
        *(ptr + i) ^= *(ptr + n - 1 - i);
    }
}

int main() 
{
    int n;
    scanf("%d", &n);

    int arr[100];
    for (int i = 0; i < n; i++) 
    {
        scanf("%d", &arr[i]);
    }

    reverse_array(arr, n);

    for (int i = 0; i < n; i++) 
    {
        printf("%d", arr[i]);
        if(i < n-1) printf(" ");
    }
    return 0;
}

Solving Approach

 

 

 

Was this helpful?
Upvote
Downvote