Reverse an Array Using Only Pointers

Code

#include <stdio.h>

void reverse_array(int *ptr, int n) {
    // Your logic here
    int tmp_val = 0;
    int *tmp = ptr;
    for (int i = 0; i < (int)(n/2); i++){
        tmp_val = *tmp;
        *tmp = *(tmp+(n-1-(2*i)));
        *(tmp+(n-1-(2*i))) = tmp_val;
        tmp++;   
    }
    //for (int k = 0; k < n; k++)
    //    printf("%d ",*(ptr + k));
}

int main() {
    int n;
    scanf("%d", &n);

    int arr[100];
    for (int i = 0; i < n; i++) {
        scanf("%d", &arr[i]);
    }

    reverse_array(arr, n);

    for (int i = 0; i < n; i++) {
        printf("%d", arr[i]);
        if(i < n-1){
            printf(" ");
        }
    }

    return 0;
}

Solving Approach