Reverse an Array Using Only Pointers

Code

#include <stdio.h>

void reverse_array(int *ptr, int n) 
{
    // Your logic here
    int temp = 0;
    int  i= n-1;
    int j = 0;
    while(j<i)
    {
    temp = (*(ptr+i));
    (*(ptr+i)) = (*(ptr+j));
    (*(ptr+j))  =   temp;
    j++;
    i--;
    }
}

int main() 
{
    int n;
    scanf("%d", &n);

    int arr[100];
    for (int i = 0; i < n; i++) {
        scanf("%d", &arr[i]);
    }

    reverse_array(arr, n);

    for (int i = 0; i < n; i++) {
        printf("%d", arr[i]);
        if(i < n-1){
            printf(" ");
        }
    }

    return 0;
}

Solving Approach