Reverse an Array Using Only Pointers

Code

#include <stdio.h>
void swap(int *a, int *b){
    int temp = *a;
    *a = *b;
    *b = temp;
}
void reverse_array(int *ptr, int n) {
    // Your logic here
    for(int i = 0; i < n / 2; i++){
       int *start = (ptr + i);
       int *end = (ptr - i + n - 1);
       swap(start, end);
    }
}

int main() {
    int n;
    scanf("%d", &n);

    int arr[100];
    for (int i = 0; i < n; i++) {
        scanf("%d", &arr[i]);
    }

    reverse_array(arr, n);

    for (int i = 0; i < n; i++) {
        printf("%d", arr[i]);
        if(i < n-1){
            printf(" ");
        }
    }

    return 0;
}

Solving Approach