Reverse an Array Using Only Pointers

Code

#include <stdio.h>

void swap(int *p1, int *p2) {
    // Your logic here
    int tmp = *p1;
    *p1 = *p2;
    *p2 = tmp;
}

void reverse_array(int *ptr, int n) {
    // Your logic here
    int* rear = ptr + n - 1;
    for(int i = 0; i < n / 2; i++){
        swap(ptr, rear);
        ptr = ptr + 1;
        rear = rear -1;
    }
}

int main() {
    int n;
    scanf("%d", &n);

    int arr[100];
    for (int i = 0; i < n; i++) {
        scanf("%d", &arr[i]);
    }

    reverse_array(arr, n);

    for (int i = 0; i < n; i++) {
        printf("%d", arr[i]);
        if(i < n-1){
            printf(" ");
        }
    }

    return 0;
}

Solving Approach