Reverse an Array Using Only Pointers

Code

#include <stdio.h>

void reverse_array(int *ptr, int n) {
    // Your logic here
    int start = 0;
    int end = n-1;
    while (start < end){
        *(ptr+start)^=*(ptr+end);
        *(ptr+end)^=*(ptr+start);
        *(ptr+start)^=*(ptr+end);
        start+=1;
        end-=1;
    }
}

int main() {
    int n;
    scanf("%d", &n);

    int arr[100];
    for (int i = 0; i < n; i++) {
        scanf("%d", &arr[i]);
    }

    reverse_array(arr, n);

    for (int i = 0; i < n; i++) {
        printf("%d", arr[i]);
        if(i < n-1){
            printf(" ");
        }
    }

    return 0;
}

Solving Approach