Reverse an Array Using Only Pointers

Code

#include <stdio.h>

void reverse_array(int *ptr, int n) {
    for(int i = 0, j = n - 1; i < j; i++,j--){
        int temp = *(ptr + i);
        *(ptr + i) = *(ptr + j);
        *(ptr + j) = temp;
    }
}

int main() {
    int n;
    scanf("%d", &n);

    int arr[100];
    for (int i = 0; i < n; i++) {
        scanf("%d", &arr[i]);
    }

    reverse_array(arr, n);

    for (int i = 0; i < n; i++) {
        printf("%d", arr[i]);
        if(i < n-1){
            printf(" ");
        }
    }

    return 0;
}

Solving Approach

• Read n and array elements.
• Use two pointers (i from start, j from end).
• Swap elements using a temporary variable.
• Print the reversed array.