Reverse an Array Using Only Pointers

Code

#include <stdio.h>

void reverse_array(int *ptr, int n) {
    int *start = ptr;          // pointer to first element
    int *end = ptr + n - 1;    // pointer to last element

    while (start < end) {
        // swap the elements
        int temp = *start;
        *start = *end;
        *end = temp;

        // move pointers
        start++;
        end--;
    }
}

int main() {
    int n;
    scanf("%d", &n);

    int arr[100];
    for (int i = 0; i < n; i++) {
        scanf("%d", &arr[i]);
    }

    reverse_array(arr, n);

    // print reversed array using only pointer arithmetic
    int *p = arr;
    for (int i = 0; i < n; i++) {
        printf("%d ", *p);
        p++;
    }

    return 0;
}

Solving Approach