Reverse an Array Using Only Pointers

Code

#include <stdio.h>

void reverse_array(int *ptr, int n) {
    // Your logic here
    int count = 0;
    int rev = n;
    while(count < n)
    { 
        *(ptr + rev) = *(ptr + count);
        rev++;
        count++;      
    }
    count = 0;
    while(count < n)
    { 
        *(ptr + count) = *(ptr + rev-1);
        *(ptr + rev-1) = 0;
        count++;
        rev--;      
    }
}

int main() {
    int n;
    scanf("%d", &n);

    int arr[100];
    for (int i = 0; i < n; i++) {
        scanf("%d", &arr[i]);
    }

    reverse_array(arr, n);

    for (int i = 0; i < n; i++) {
        printf("%d", arr[i]);
        if(i < n-1){
            printf(" ");
        }
    }

    return 0;
}

Solving Approach