Reverse an Array Using Only Pointers

Code

#include <stdio.h>

void reverse_array(int *ptr, int n) {
    if( n <= 0) return;
    // Your logic here
    int *start = ptr;
    int *end = &ptr[n-1];
    while(n>1){
        *start += *end;
        *end = *start - *end;
        *start = *start - *end;
        n -= 2;
        start++;
        end--;
    }
}

int main() {
    int n;
    scanf("%d", &n);

    int arr[100];
    for (int i = 0; i < n; i++) {
        scanf("%d", &arr[i]);
    }

    reverse_array(arr, n);

    for (int i = 0; i < n; i++) {
        printf("%d", arr[i]);
        if(i < n-1){
            printf(" ");
        }
    }

    return 0;
}

Solving Approach