Reverse an Array Using Only Pointers

Code

#include <stdio.h>

void swap(int* i, int* j)
{
    int temp = *i;
    *i = *j;
    *j = temp;
}

void reverse_array(int *ptr, int n) {
    // Your logic here
    int i = 0;
    int j = n-1;
    while(i < j)
    {
        swap((ptr + i), (ptr + j));
        i++; j--;
    }
}

int main() {
    int n;
    scanf("%d", &n);

    int arr[100];
    for (int i = 0; i < n; i++) {
        scanf("%d", &arr[i]);
    }

    reverse_array(arr, n);

    for (int i = 0; i < n; i++) {
        printf("%d", arr[i]);
        if(i < n-1){
            printf(" ");
        }
    }

    return 0;
}

Solving Approach