Reverse an Array Using Only Pointers

Code

#include <stdio.h>

void reverse_array(int *ptr, int n) {
    // Your logic here
    int copy_num;
    int s_idx = 0, e_idx = n-1;


    while(s_idx != e_idx)
    {
        copy_num = *(ptr + s_idx);
        *(ptr + s_idx) = *(ptr + e_idx);
        *(ptr + e_idx) = copy_num;

        if(n %2 == 0 && (e_idx - s_idx) == 1)
        {
            return;
        }
        e_idx--;
        s_idx++;
    } 
}

int main() {
    int n;
    scanf("%d", &n);

    int arr[100];
    for (int i = 0; i < n; i++) {
        scanf("%d", &arr[i]);
    }

    reverse_array(arr, n);

    for (int i = 0; i < n; i++) {
        printf("%d", arr[i]);
        if(i < n-1){
            printf(" ");
        }
    }

    return 0;
}

Solving Approach

 

 

 

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Input

5 1 2 3 4 5

Expected Output

5 4 3 2 1