Reverse an Array Using Only Pointers

Code

#include <stdio.h>
#include <stdint.h>

void reverse_array(int *ptr, int n) {
    // Your logic here
   if(!ptr || n<=1) return;

   int *left=ptr;
   int *right=ptr+n-1;
   while(left<right)
   {
     int tmp=*left;
     *left=*right;
     *right=tmp;
     left++;
     right--;
   }

}

int main() {
    int n;
    scanf("%d", &n);

    int arr[100];
    for (int i = 0; i < n; i++) {
        scanf("%d", &arr[i]);
    }

    reverse_array(arr, n);

    for (int i = 0; i < n; i++) {
        printf("%d", arr[i]);
        if(i < n-1){
            printf(" ");
        }
    }

    return 0;
}

Solving Approach