Reverse an Array Using Only Pointers

Code

#include <stdio.h>

void reverse_array(int *ptr, int n) {
    // Your logic here
    int* start = ptr; int* end = ptr + (n-1);
    // printf("ptr: %x\n", ptr);
    // printf("start: %x\n", start);
    // printf("end:  %x\n", end);
    // printf("*ptr: %x\n", *ptr);
    // printf("*start: %x\n", *start);
    // printf("*end:  %x\n", *end);
    while(start < end){
        int tmp = *start;
        *start = *end;
        *end = tmp;
        start++; end--;
    }
}

int main() {
    int n;
    scanf("%d", &n);

    int arr[100];
    for (int i = 0; i < n; i++) {
        scanf("%d", &arr[i]);
    }

    reverse_array(arr, n);

    for (int i = 0; i < n; i++) {
        printf("%d", arr[i]);
        if(i < n-1){
            printf(" ");
        }
    }

    return 0;
}

Solving Approach