Rotate Right in a 32-bit Register

Code

#include <stdio.h>
#include <stdint.h>

#define himask 0x80000000
#define lomask 1

uint32_t rotate_right(uint32_t reg, uint8_t n) {
    // Your code here
    uint8_t i;
    for (i=0; i < n; i++) {
        if (reg & lomask) {
            reg = (reg >> 1) | (himask);
        }
        else
        {
            reg = (reg >> 1);
        }
    }
    return reg;
}

int main() {
    uint32_t reg;
    uint8_t n;
    scanf("%u %hhu", &reg, &n);
    printf("%u", rotate_right(reg, n));
    return 0;
}

Solving Approach

check the rightmost bit before shifting right

if it is one, then shift and ad a one on the left

else just shift right one bit 

repeat to exjaust n